[Solved] Size difference between *A and A[0]

Gendozz Asks: Size difference between *A and A[0]

void Size(int A[], int size){
    printf("Size of A = %dnSize of A[0] = %dnn", sizeof(A), sizeof(A[0]));

when doing so I get an unexpected answer:

Size of A = 8
Size of A[0] = 4

As I know while we pass array to a function we use “pass by reference” and by checking sizeof(A) we should get the size of array type. May you help me solve this problem please?

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